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6x^2-15x-34=2
We move all terms to the left:
6x^2-15x-34-(2)=0
We add all the numbers together, and all the variables
6x^2-15x-36=0
a = 6; b = -15; c = -36;
Δ = b2-4ac
Δ = -152-4·6·(-36)
Δ = 1089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1089}=33$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-33}{2*6}=\frac{-18}{12} =-1+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+33}{2*6}=\frac{48}{12} =4 $
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